There are two peice pf gold and silver alloy. The ratio between the gold and silver in the first piece is 2:3, in the second peice 3:7. If we want to have 8 gram of gold and silver alloy with gold-silver ratio 5:11 how much of each peice of alloy is needed.

Step-by-step explanation:

The ratio between the gold and silver in the first piece = 2:3

The ratio between the gold and silver in the second piece =3:7

The ratio in the mixture = 5:11

We want to have 8 gram of the new mixture.

Let the gram of alloy taken from the first piece=x

Therefore: gram of alloy would be taken from the second piece=(8-x)

This gives:

We simplify the equation above for the value of x.

Therefore to create 8 gram of gold and silver alloy with gold-silver ratio 5:11, we take 1 grams of one of the alloy and 7 grams of the other alloy.

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