At open skate night, admission is $3.75 with a membership card and $5.00 without a membership card. skate rentals are $3.00.
the moores and cotters were at open slate night. the moores paid $6.00 more for skate rentals than the cotters did. together, the two families paid $30 for skate. how many pairs of skates did the moores rent?

Step-by-step explanation:

The problem doesn't specifies which family has membership card, and which one doesn't.

According to the problem, The Moore's paid $6.00 more than the Cotter's. Both families paid $30. So, with this relations we can solve the problem.

The difference between families is represented by:

And the total amount of money is:

Replacing the first equation in the second one:

Replacing this value in the second equation, we have:

According to these results, the Moore's rented 18 pair of skates, and the Cotter's 12 pairs.

If Skate rental are $3.00, then:

The Moore spent 3(18)=$54.

The Cotters spent 3(12)=$36.

idk lol xd

step-by-step explanation:

ez do it yourself lazy

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!