The mean of 4 data values is calculated. One of the data values is 3 above
the mean. Another value is 4 above the mean. A third value is 1 above the
mean. What is true about the fourth data value? olla
A It is 8 below the mean.
B It is 6 below the mean.
C It is equal to the mean.
D It is 2 above the mean.

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  A.  It is 8 below the mean

Step-by-step explanation:

The sum of differences from the mean is always zero. If x is the difference from the mean that the fourth data value has, then we must have ...

  3 + 4 + 1 + x = 0

  x = -8 . . . . . . . . . subtract 8

The fourth data value must be 8 below the mean.

Additional comment

I find this property of the mean to be very useful in solving any number of problems related to differences from an actual or a desired mean.

i'm sure goog can you get that answer

on a coordinate grid, point a is at (−4.0, −2.4) and point b is at (4.0, −2.4). point b is a reflection of point a across the –axis. input either a lowercase x or i think is the right awnser

step-by-step explanation: