Among a banks 214 customers with checking or savingsaccounts, 189 have checking accounts, 73 have regular savingsaccounts, 114 have money market savings accounts, and 69 have bothchecking and regular savings accounts. No customer is allowed tohave both savings and money market savings accounts.
a.) How many customers have both checking and money marketsavings accounts?
b.) How many customers have a checking account but no savingsaccount?

a) 93 customers

b) 27 customers

Step-by-step explanation:

Total number of customers (n) = 214

Checking (C) = 189

Regular Savings (R) = 73

Market Savings (M) = 114

Checking and Regular (C&R) = 69

a) The total number of customers is given by:

93 customers have both checking and money market savings accounts

b) The number of customers with savings accounts is given by:

27 customers have a checking account but no savings account.

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explanation

the graph has a slope of 1/3 because each time you move up 1, you go to the right 3. so, slope = rise/run = 1/3. we can cross choice a off the list since we want a slope of 3, rather than 1/3.

the first table shown has a slope of -3. this is because the rise is -6 and the run is 2, so slope = rise/run = -6/2 = -3. note how x increases by 2 each time (run) and y drops by 6 each time (rise). choice b can be eliminated.

the second table has a slope of 3. each time x goes up by 1, the y values increase by 3. slope = rise/run = 3/1 = 3. alternatively you can use the slope formula to prove that the slope is 3 here. use any two rows of values to generate the two points. choice c is one of the answers

the third table also has a slope of 3. let's use the slope formula to prove as such. i'm going to use the first two rows of the table. so i'll use the two points (2,1) and (5,10)

m = slope

m = (y2-y1)/(x2-x1)

m = (10-1)/(5-2)

m = 9/3

m = 3 so we get a slope of 3

choice d is the other answer

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c