Mike discovered that the pool in his backyard is leaking slowly. The pool holds 18,968 gallons of water, and is leaking at a rate of 12 gallons per day. If mike does not replace the water that has leaked from the pool, how many gallons of water will remain in the pool after 68 days?

18,152 Gallons

Step-by-step explanation:

First, you'll want to put this into an equation. We'll use x as the amount of water in gallons that will remain in the pool.

18,968 - 12 (68) = x

First, we'll multiply - 12 and 68.

We'd end up with this:

18,968 - 816 = x

From here, we can just subtract 816  from 18,968.

18,152 = x

Now we can see that there will be 18,152 gallons of water left in the pool after 68 days.

answer: are you

step-by-step explanation:

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2