Using the zero product property solve for the x values given (3x-2)(x+1)=0.

x=2/3, x=-1

Step-by-step explanation:

(3x-2)(x+1)=0

1) if (3x-2)=0

that x value equal to:

x=2/3

(3(2/3)-2)=(2-2)=0

then 0 times (x+1)=0

2) if (x+1)=0

then x value will be equal to:

x=0-1

x=-1

(3(-1)-2)(-1+1)=(-3-2)(0)=-5 times 0= 0

hello from mrbilldoesmath!

answer:

the domain is the set { -2, 0, 2, 3}

discussion:

the domain is the set of x values in the ordered pairs (x,y). taking the x, or first component, of each ordered pair gives   -2, 0, 2, 3.

you,

mrb