Graph a line that contains the point (-5,-3) and has a slope of -2

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Step-by-step explanation:

Graph (-5,-3) and use the slope, -2, to find another point. -2 can also be written as

and   **

Use both. This works because either way, they will lie on the same line with the same slope. So, starting at (-5,-3), go down two points (-)* and to the left 1 (+)*, then, starting at (-5,-3) again, go up two points (+)* then to the right 1 point (-)*.

* If the number is negative, you either go down or to the right. If the number is positive, you go up and to the left.

**Rise over run refers to the change in the y-axis and the change in the x-axis: . Only one number is negative because, if both were negative, that would make a positive number, but the slope is -2, not 2.

Another way you could do this is by finding points first. All you need to do is turn the slope into a "point". Remember, 2 is the y and 1 is the x:

and

Then, using (-5,-3) and your new points, add them separately:

(-4,-5) is one point

(-6,-1) is another point. Connect the three points. You can check your work on the graph:

The equation of the line is y = -2x - 7 and the graph is attached

A linear equation is in the form:

y = mx + b

where y, x are variables, m is the slope of the line and b is the y intercept.

The equation of the line that contains the point (-5,-3) and has a slope of -2 is:

The equation of the line is y = -2x - 13 and the graph is attached

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rectangle: 9 1/8 x 4 1/9 = 37 37/72in

parallelogram: b times h= 10.3 x 6.2 = 63.86

trapezoid: a+b/2 times h= 42.5

volume of prism: l times w times h= 36

-1/2 +2

step-by-step explanation: