Probability word problem

In a group of 30 students, there are 14 girls and 4 of them can speak French. 6 of the 16 boys can speak French. If a student is selected randomly from the group, find the probability that the selected student:

a) can speak French:

b) is a boy:

c) is a girl who can speak French:

see below

Step-by-step explanation:

A can speak french

There are 10 students who can speak french, 4 girls and 6 boys

P(french) = speak french/ total

                = 10/30

                  = 1/3

B is a boy

There are 16 boys

P (boy) = boys/total

            = 16/30

             8/15

C girl who can speak french

There are 4 girls who can speak french

P (girl who can speak french) = girl who can speak french/ total

                                                   =4/30

                                                     2/15

a) 1/3

b) 8/15

c) 2/15

Step-by-step explanation:

Total students: 30

Girls: 14

Boys: 30 - 14 = 16

French speaking: 4 + 6 = 10

a) P(French speaking) = 10/30

1/3

b) P(boy) = 16/30 = 8/15

c) P(French speaking girl) = 4/30

= 2/15

heyyy

step-by-step explanation:

, and

for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

note the following:

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for