Use substitutions to solve each system of equations.[y = 4x -6] [5x + 3y = 1]

y=4x-6(1)

5x+3y=1(2)

substitute y=4x-6 into equation 2

5x+3(4x-6)=1

5x+12x-18=1

17x=19

x=1.12

substitute x=1.12 into equation 1

y=4(1.12)-6

y=4.48-6

y=-1.52

x=1.12,y=1.52

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10

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