If six people decide to come to a basketball game, but three of them are only 2/5 sure that they will stay for the entire time (the other three are sure they'll stay the whole time), what is the probability that at the end, at least 5 people stayed the entire time

the probability that at the end, at least 5 people stayed the entire time = 0.352

Step-by-step explanation:

From the question, 3 of the people are sure to stay the whole time. So, we'll deduct 3 from 6.which leaves us with 3 that are only 2/5 or 0.4 sure that they will stay the whole time.

Thus, what we need to compute to fulfill the probability that at the end, at least 5 people stayed the entire time of which we know 3 will stay, so for the remaining 3,we'll compute;

P[≥2] which is x~bin(3,0.4)

Thus;

P(≥2) = (C(3,2) x 0.4² x 0.6) + (C(3,3) x 0.4³)

P(≥2) = 0.288 + 0.064

P(≥2) = 0.352

the ratio of white tiles to blue tiles is 48: 16. the ratio in it's simplest form is 3: 1.

step-by-step explanation:

ratio: take the first number and add a colon next to it, then add the second number after that. make sure the ratio order matches up with the written problem!

simplest form: we can simplify the ratio 48 : 16 by dividing both terms by the greatest common factor (gcf).

the gcf of 48 and 16 is 16.

divide both terms by 16:

48 ÷ 16 = 3

16 ÷ 16 = 1

reducing to simplest form:

48 : 16 = 3 : 1

- 70

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