OA

⊥

OC

start overline, O, A, end overline, \perp, start overline, O, C, end overline

\qquad m \angle AOB = 6x - 12^\circm∠AOB=6x−12

∘

m, angle, A, O, B, equals, 6, x, minus, 12, degrees

\qquad m \angle BOC = 3x + 30^\circm∠BOC=3x+30

∘

m, angle, B, O, C, equals, 3, x, plus, 30, degrees

Find m\angle AOBm∠AOBm, angle, A, O, B:

dsfdsf

step-by-step explanation:

fddsf

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

cbnygjdyj

step-by-step explanation: