The system of equations {y=4x} {y-4=4(x-1) what solution does it has.

(y = 4 x, y - 4 x = 0)

Step-by-step explanation:

Expand the following:

(y = 4 x, y - 4 = 4 (x - 1))

4 (x - 1) = 4 x - 4:

(y = 4 x, y - 4 = 4 x - 4)

Subtract 4 x - 4 from both sides of y - 4 = 4 x - 4:

(y = 4 x, y - 4 - 4 x - 4 = (4 x - 4) - 4 x - 4)

(4 x - 4) - (4 x - 4) = 0:

(y = 4 x, y - 4 - (4 x - 4) = 0)

-(4 x - 4) = -(-4) - 4 x:

(y = 4 x, y - 4 + -(-4) - 4 x = 0)

-(-4) = 4:

(y = 4 x, y - 4 + 4 - 4 x = 0)

Grouping like terms, y - 4 + 4 - 4 x = y - 4 x + (4 - 4):

(y = 4 x, y - 4 x + (4 - 4) = 0)

4 - 4 = 0:

(y = 4 x, y - 4 x = 0)

ou would have 12 of each

so then what are you asking?

step-by-step explanation: