The number y of Northern Rocky Mountain wolf breeding pairs x years since 1990 can be modeled by the function y=0.20x^2+1.8x−3 . When were there about 32 breeding pairs? Show your work. (Within "Text Editor", there is an option that looks like the "square root of x." This option allows you to type math. It is best for showing the solving of quadratic equations.) Then, state the approximate year(s) when this happened, if possible.

; )

step-by-step explanation: ; )

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

you probably already have the answer but anyways it's b. 15.0

step-by-step explanation: