If we take samples from normal populations and construct two confidence intervals (CI) for which the only difference is that one of them was at the 80% confidence level and the other was at the 90% level, which of the following statements is true? Group of answer choices The margin of error is larger in the 90% CI than in the 80% CI. The margin of error is the same in the 90% CI as it is in the 80% CI. The margin of error is smaller in the 90% CI than in the 80% CI. There is not enough information to determine which of the above statements is true.

The margin of error is larger in the 90% CI than in the 80% CI.

Step-by-step explanation:

Confidence interval is written as

Sample mean ± margin of error

Margin of error = z × population standard deviation/number of samples

The z score for a 90% confidence level(1.645) is higher than the z score for a 80% confidence level(1.282)

If all other parameters(sample size and population standard deviation) remain the same, then the true statement is

The margin of error is larger in the 90% CI than in the 80% CI.

8 apples are left.

step-by-step explanation:

10-2=8

10 apples

take 2

now u have 8

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )