Suppose a normal distribution has a mean of 48 and a standard deviation of 2. What is the probability that a data value is between 46 and 47? Round your answer to nearest tenth of a percent.

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

answer: 48

just remember to use pemdas:

parentheses

expressions

multiplication

division

addition

subtraction

answer: 80,000

step-by-step explanation:

the population doubles every day.

10,000*2=20,000 day 4

20,000*2=40,000 day 5

40,000*2=80,000 day 6