Describe the sampling distribution of ModifyingAbove p with caretp. Assume the size of the population is 30 comma 00030,000. nequals=900900, pequals=0.50.5 Choose the phrase that best describes the shape of the sampling distribution of ModifyingAbove p with caretp below. A. Not normal because n less than or equals 0.05 Upper Nn≤0.05N and np (1 minus p )greater than or equals 10.np(1−p)≥10. B. Approximately normal because n less than or equals 0.05 Upper Nn≤0.05N and np (1 minus p )less than 10.np(1−p)<10. C. Approximately normal because n less than or equals 0.05 Upper Nn≤0.05N and np (1 minus p )greater than or equals 10.np(1−p)≥10. D. Not normal because n less than or equals 0.05 Upper Nn≤0.05N and np (1 minus p )less than 10.

on a coordinate grid, point a is at (−4.0, −2.4) and point b is at (4.0, −2.4). point b is a reflection of point a across the –axis. input either a lowercase x or i think is the right awnser

step-by-step explanation:

third choice down

step-by-step explanation:

the first inequality is based on the number of adults and campers, and the second inequality is based on the cost of feeding both the adult and the camper.

we know that there is room for 525 people max.   it's ok to have less than 525, but it's not ok to have more than 525, so the inequality is less than or equal to.   the number combination of adults (x) and campers (y) cannot exceed this 525 max.   therefore:

x + y ≤ 525

now we talk about cost.   it costs $9 to feed one adult, so depending upon the number of adults you have (x) depends upon how much it will cost to feed that number of adults.   same with the campers, who cost $5 to feed.   the adults can be represented by 9x and the campers can be represented by 5y.   since the budget cannot exceed 1,200, the second inequality is:

9x + 5y ≤ 1200

5 feet of chain cost $9

so the answer is 1.80

the given growth  function for the length of the fish (cm) is

f(m) = 5(1.07)m = 5.35m

where 

m = months

at the end of the study, the length is 9.19 cm. the  time for conducting the study is determined as

5.35m = 9.19

m = 1.7178 months

part a.

the study was performed over a time period  of about 1.72 months. therefore  the domain for  plotting the function is 0 < = m < = 1.72.

note:

if growth  continues at this rate for up to m months, then the domain would be 0< =m< =m.

part b.

the growth function is a linear function.

when m=0, f=0.

therefore the initial growth is zero, which represents the y-intercept.

part c.

assume that the growth function is valid for 0< =m< =9.

the average rate of change of the function is the slope of the linear function, which is 5.35 cm/month.