A bag contains 5 yellow blocks, 2 green blocks and 3 blue blocks. If you choose one block and then another block without putting the first one back in the bag, what is the probability that the first block will be green and the second will be yellow

The probability that the first block will be green and the second will be yellow is    or 0.111.

Step-by-step explanation:

We are given that a bag contains 5 yellow blocks, 2 green blocks and 3 blue blocks.

Also, we choose one block and then another block without putting the first one back in the bag.

Firstly, as we know that Probability of any event is given by ;

           Probability of an event  =    

SO, Probability that the first block will be green =  

Here, Number of green blocks = 2

Total number of blocks in bag = 5 yellow + 2 green + 3 blue = 10 blocks

So, Probability that the first block will be green  =  

Similarly, Probability that the second block will be yellow =  

Here, Number of yellow blocks = 5

Total number of remaining blocks in bag = 10 - 1 = 9 blocks  {because we haven't put the block back after choosing the first}

So, Probability that the second block will be yellow  =  

Now, Probability that the first block will be green and the second will be yellow  =  

            =    = 0.111

Hence, the required probability is 0.111.

x = 10.1

step-by-step explanation:

all of the angles of a tirangle add up to 180º

180 - 65 = 115 (since we already know the value of one angle)

(2x + 7) + (8x + 7) = 115

(combins like terms) 10x + 14 = 115

(isolate the variable subtract 14 from both sides): 10x = 101

(find the variable divide both sides by 10): x = 101/10

x = 10.1

i can't read the graph

step-by-step explanation: