Find the equation of the line that is perpendicular to y = 2x + 8 and passes though the point (8, –8).

y= -1\2x-4

Step-by-step explanation:

y=mx+c

perpinicular means you flip the slop and change the sign so the slope(m) become -1\2

y=-1\2x+c

since he gives you (8,-8) meaning x=8 and y= -8

we substitute

-8=(-1\2 x 8) +c

now we isolate c

-8+4=c

c=-4

the equation will be

y= -1\2x-4

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

it would open into a square depending on the type of envelope i’m not sure about the second part