Help me pls ill give
64−(3y+8y+y)÷40=37

64 - (3y + 8y + y) / 40 = 37

Simplify 3y + 8y + y

64 - 12y / 40 = 37

Add 12y / 40 to both sides and subtract 37

27 = 12y / 40

Multiply both sides by 40

1080 = 12y

Divide both sides by 12

90 = y

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.