Use elimination to solve each system of equations.

please help me im dying

2x - y = -1

3x - 2y = 1

2x - y = -1

3x - 2y = 1

Multiply the first equation by -2

-4x + 2y = 2

Add the new equation to the second equation

-x = 3

x = -3

Plug -3 into the first equation

2 * -3 - y = -1

-6 - y = -1

-y = 5

y = -5

(-3, -5)

Step-by-step explanation:

Elimination essentially means that we need to eliminate one variable so that we're left with only one to deal with. For this problem, let's eliminate y.

Multiply the first equation by 2:

2 * (2x - y) = (-1) * 2

4x - 2y = -2

Now, subtract the second equation from this new "first" equation:

   4x - 2y = -2

-   3x - 2y = 1

    x  +  0y = -3

So, we see that x = -3. We can now substitute this value of x into one of the equations and solve for y:

2x - y = -1

2 * (-3) - y = -1

-6 - y = -1

y = -5

Thus, the solution is (-3, -5).

Hope this helps!

29 mil

step-by-step explanation:

d) 30 units^2

area of rectangle = l × b

we know,

length = 10 unit

breadth = 3 unit

applying the formula,

= l × b

= 10 × 3

= 30 unit^2

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