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a catapult launches a boulder with an upward velocity of 112 ft/s. the height of the boulder, h, in feet after t seconds is given by the function h= -16t^2 + 112t +30 how long does it take the boulder to reach its maximum height? what is the boulder’s maximum height? round to the nearest hundredth, if necessary.

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

i think it will be zero as slope has a formula of difference between initial and final distance divided by itz time interval