In RST, X is the midpoint of RS and Y is the midpoint of RT. Given that XY = 3z + 2 and ST = 7z - 1, what is the value of z?

The required value of z is 5.

Given that,

In RST, X is the midpoint of RS,

And Y is the midpoint of RT.

XY = 3z + 2 and ST = 7z - 1.

We have to determine,

What is the value of z.

According to the question,

X is the midpoint of RS,

And Y is the midpoint of RT.

Therefore,

Putting the value of XY and ST in the equation,

XY = 3z + 2 and ST = 7z - 1.

Then,

Hence, The required value of z is 5.

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Step-by-step explanation:

XY=ST/2

3z+2=(7z-1)/2

2*(3z+2)=7z-1

2*3z+2*2=7z-1

6z+4=7z-1

+1         +1

6z+5=7z

-6z      -6z

5=z

answer: i'm not sure

step-by-step explanation:

b. 18

step-by-step explanation:

so the equation for this is:

ab^2=ac⋅ad

ab being the top length of 6 and ac being the length of 2 and ad being the length of x. let's plug into the equation:

6^2 = 2x

now lets just solve for x:

36 = 2x

18 = x

i hope that !