Suppose AC = 5 cm, BC = 12 cm, and mAC = 45.2°.
To the nearest tenth of a unit, the radius of the circumscribed circle
is __?__ cm and m∠OAC = __?__°.

Help pls

9514 1404 393

Step-by-step explanation:

AB is shown as a diameter, which means that inscribed angle C is a right angle. The length of the diameter can be found from the Pythagorean theorem to be ...

  AB^2 = AC^2 + BC^2

  AB = √(5^2 +12^2) = 13

The radius is half the length of the diameter, so is ...

  OA = 13 cm/2 = 6.5 cm . . . . radius

__

The measure of inscribed angle B is half the measure of arc AC, so is ...

  ∠B = 45.2°/2 = 22.6°

The measure of angle OAC is the complement of this, so is ...

  ∠OAC = 90° -22.6°

  ∠OAC = 67.4°

Step-by-step explanation:

b

step-by-step explanation:

a difference is the result of subtraction. while each of these expressions has subtraction in it, a difference will be the result when subtraction is the last operation applied in the order of operations for the expression. this means subtraction must be outside of the parenthesis. only b has this.