Please help asap

brainliest answer and five star rating

Here are three systems of equations. Which method (graphing, substitution, elimination) would you choose to solve and why. Use each method only once.

System #1 System #2 System #3

2x + 3y = 12 y = 2x +1 x = 2y + 5
4x + 3y = 18 y =-3x -2 x + 3y = 25

System #1

2x + 3y = 12   and  4x + 3y = 18

I'd use elimination on this one; we subtract equations and the 3y disappears,

2x = 6

x = 3

3y = 18-4x = 18 - 4(3) = 18 = 12 = 6

y = 2

System #2

y = 2x +1  and  y =-3x -2

Here I'd use elimination; we have two things equal to y, we eliminate y by setting the right sides equal to each other,

2x + 1 = -3x - 2

5x = -3

x = -3/5

y = 2x+1 = -1/5

check y=-3x -2 = 9/5 - 10/5 = -1/5, good

System #3

x = 2y + 5  and x + 3y = 25

Here I'd use substitution.   The first equation is for x in terms of y; if we substitute it into the second equation we'll just have an equation in y.

(2y + 5) +3y = 25

5y + 5 =25

5y = 20

y = 4

x = 2y+5 = 13

center= (-2,0)

radius= sqrt2/2

step-by-step explanation:

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