A machine produces ball bearings with diameters that have a normal distribution with known standard deviation of 0.04 centimeters. Ball bearings with diameters that are too small or too large are undesirable. The machine is out of calibration if the machine's average output differs from 0.50 cm. Assume that a technician randomly samples 25 bearings which had a mean diameter of 0.51 centimeters.

The technician wants to perform a hypothesis test to determine whether the machine is out of calibration. State the appropriate null and alternate hypotheses.

A) H0: μ ≠ 0.50, H1: μ = 0.50

B) H0: μ = 0.50, H1: μ ≠ 0.50

C) H0: μ = 0.50, H1: μ > 0.50

D) H0: μ = 0.50, H1: μ < 0.50

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse

5/20 so 25%

step-by-step explanation:

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

hello, sorry being so rude after all that fighting i found it kind of funny, so as me saying sorry here is an answer!

since the table showed her that   2km = 2000m.

to determine, how many km in 2000m, she would divide by 1000.

= 2000 / 1000 = 2 km.

similarly, for 8000m = 8000 / 1000 = 8 km

cheers to savings

~

your pal papaguy