A good rule of thumb is to design the horizontal stabilizer so that its area is about 1/6 to 1/8 of the area of the wing. If the area of the wing is 101.25 cm2, which of the following would be a good horizontal stabilizer design?
Answer choices:
Stabilizer with area = 32 cm2.
Stabilizer with area = 20 cm2.
Stabilizer with area = 14 cm2.
Stabilizer with area = 11 cm2.

Stabilizer with area = 14 cm².

Step-by-step explanation:

Area of the wing = 101.25 cm²

Rule of the thumb is that area of stabilizer must be about 1/6 to 1/8 of the area of wing. So, first we calculate 1/6 of the area of the wing and 1/8 of the area of the wing. Area of stabilizer must be in between these two numbers.

1/6 of the area of wing =

1/8 of the area of wing =

This means, the area of horizontal stabilizer must be in between 12.656 cm² and 16.875 cm². From the given options only one option lies in between these two numbers and that is 14 cm²

Therefore, area of a good stabilizer design from the given options would be 14 cm²

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step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet