A jar contains three red marbles and five green marbles. A marble is drawn at random and not replaced. A second marble is then drawn from the jar. Find the probability that the first marble is red and the second marble is green.

3/28

Step-by-step explanation:

3 red+ 5 green = 8 marbles in the jar

1st marble:

P(red) = number of red/ total = 3/8

We keep the marble

2 red+ 5 green = 7 marbles in the jar

P(green) = number of green/ total = 2/7

P (red,keep,green) = P(red)* P(green) = 3/8*2/7 = 6/56 = 3/28

ion

step-by-step explanation:

ion ion ion ion ion ion ion ion ion ion ion

10 down (bang1)

5 up

5down (2)

2.5 up

2.5 down (3)

1.25 up

1.25 down (4)

now add them up : )

hoped i lol