Find x. trianges. my question is attached.

This triangle is a special triangle: 45 - 45 - 90

Both of the legs (L) have the same value. The hypotenuse is H = L√2

So instead of L, you would put the value of the leg, which you have is 4

The hypotenuse, or x, is equal to 4√2

It will be b=4√2
PROCEDURE:
it will be solved with the help of trigonometric ratios
sin θ = perp/hyp
hyp= perp/sin θ
hyp= 4/sin45
hyp=4/(√2/2)
hyp=(4*2)/√2
hyp=8/√2
hyp=(8/√2)*(√2/√2)
hyp=(8√2)/(√2*√2)
hyp=(8√2)/2
hyp=4√2 answer