Thirty­two cyclists make a seven day trip. Each cyclist requires 8.33 kg of food for the entire trip. If each cyclist wants to eat an equal amount of food each day, how many kg of food will the group be carrying at the end of day 5? 13 Hands­on experience. See pg. 2.D.4 for prep work and procedure. 14 Hands­on experience. See pg. 2.D.17 for prep work and procedure.

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

the answer is 0.8in^2

hope you get it down chief.