Please help

Find the polynomial M if 2x^2− 1/3 ax+by−M=0.

Find the polynomial B if 3x^2y− 1/3 xy^3+cy+B=0.

The Y for the second equation is not an exponent.

Thank You

M = 2x² - (ax/3) + by

B = - 3x²y + (xy³/3) - cy

Step-by-step explanation:

Equation 1 is

2x² - (1/3)ax + by - M = 0

M = 2x² - (ax/3) + by

Equation 2

3x²y - (1/3)xy³ + cy + B = 0

B = - 3x²y + (xy³/3) - cy

Hope this Helps!!!

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step-by-step explanation:

2/5+1/2=9/10

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step-by-step explanation: