The box plots represent daytime high temperatures during the month of April in two cities. 2 box plots. The number line goes from 20 to 70. For City A, the whiskers range from 30 to 63, and the box ranges from 50 to 60. A line divides the box at 55. For City B, the whiskers range from 40 to 70, and the box ranges from 43 to 55. A line divides the box at 53. Which of the following inferences can you make? Check all that apply. City A tends to be warmer than City B. City B tends to be warmer than City A. City A has more variable temperatures than City B. City B has more variable temperatures than City A. City A has the highest April temperature.

The correct options are;

City A tends to be warmer than City B

City A has more variable temperatures than city B

Step-by-step explanation:

For City A

The number line is from 20 to 70

The whiskers range = 30 to 63

The box range = Interquartile range = 50 to 60

Therefore;

Q₁ = 50

Q₃ = 60

The median = Q₂ = 55

For City B

The number line is from 20 to 70

The whiskers range = 40 to 70

The box range = Interquartile range = 43 to 55

Therefore;

Q₁ = 43

Q₃ = 55

The median = Q₂ = 53

Therefore;

The range of a box plot for City A is 63 - 30 = 33

The range of a box plot for City B is 70 - 40 = 30

The interquartile range for City A = 60 - 10 = 10

The interquartile range for City B = 55 - 43 = 12

The minimum temperature for City A = 30

The maximum temperature for City A = 63

The minimum temperature for City B = 40

The maximum temperature for City B = 70

Comparing the averages of the temperatures of each quartile, we have;

For City A

Total average temperature, T₁

T₁ = 0.25*40*30 + 0.25*52.5*30+0.25*57.5*30+0.25*61.5*30 = 1586.25

For City B

Total average temperature, T₂

T₂ = 0.25*41.5*30 + 0.25*48*30+0.25*54*30+0.25*62.5*30 = 1545

Hence, T₁ > T₂

Therefore, City A tends to be warmer than City B

Also

City A has more variable temperatures than city B as the range is larger and   25% of City B are between 40 and 43 and another 25% is between the temperatures of 53 and 55 and also 75% of City B are between 40 and 55 while 75% of City A are between 60 and 30.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2