The bar graph shows the number of school days Jalen had homework and did not have homework during the first six months of
school. During how many months was the difference between the number of days with homework and with no homework greater than 6?

Given:

In July:

Number of days he has done the homework = 6

Number of days he has not done the homework = 4

In August:

Number of days he has done the homework = 16

Number of days he has not done the homework = 7

In September:

Number of days he has done the homework = 14

Number of days he has not done the homework = 4

In October:

Number of days he has done the homework = 14

Number of days he has not done the homework = 8

In November:

Number of days he has done the homework = 16

Number of days he has not done the homework = 4

In December:

Number of days he has done the homework = 5

Number of days he has not done the homework = 10

To find the months in which the difference between the number of days with homework and with no homework greater than 6.

Now,

In July,

The difference between the number of days with homework and with no homework = 6-4 = 2

In August,

The difference between the number of days with homework and with no homework = 16-7 = 9

In September,

The difference between the number of days with homework and with no homework = 14-4 = 10

In October,

The difference between the number of days with homework and with no homework = 14-8 = 6

In November,

The difference between the number of days with homework and with no homework = 16-4 = 12

In December,

The difference between the number of days with homework and with no homework = 10-5 = 5

Hence,

In 3 months the difference between the number of days with homework and with no homework greater than 6 and these are: August, September, November.

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.