If parallelogram jklm is rotated 270° counterclockwise around the origin, what are the coordinates of the endpoints of the side congruent to side kl in the image parallelogram? a. k’(-4, -6); l’(3, -3) b. k’(6, 4); l’(3, 3) c. k’(-6, -4); l’(-3, -3) d. k’(-4, 6); l’(-3, -3)

The correct answer is:

B) K’(6, 4); L’(3, 3)

Explanation:

A 270° clockwise rotation maps every point (x, y) to (y, -x). (It negates the x-coordinate and then switches it and the y-coordinate.)

This means the endpoints of the side congruent to KL, K' and L', would be mapped as:

K'(-4, 6)→(6, 4)

L'(-3, 3)→(3, 3)

first anwser choice.

step-by-step explanation:

the greater/less or equal to symbol (> or < with the line at the bottom) is a closed/filled in circle.

-5c + 2 _< _27

subtract from both sides by 2

-5c _< _ 27

divide both sides by -5

c _< _ 5.4

flip the inequality sign

c _> _5.4

the only possible answer that would match the simplified inequality is the first answer choice