What is the area of the trapezoid shown? Express your answer in simplest exact form.
[asy]
unitsize(1.5cm);
pair a=(0,0); pair b=(1,sqrt(3)); pair c=(3,sqrt(3)); pair d=(4,0);
draw(a--b--c--d--a);
label("2",(a+b)/2,NW);
label("2",(b+c)/2,N);
label("2",(c+d)/2,NE);
label("~$60^\circ$",a, NE);
label("$60^\circ$~",d, NW);
[/asy]

step-by-step explanation:

hjkj

the answer is c.

step-by-step explanation:

18 units²

step-by-step explanation:

first let's find altitude bd using the distance formula

d = √((y₂ - y₁)² + (x₂ - x₁)²)

bd = √((0 - -3)² + (0 - 3)²)

bd = √18

given the placement of points a and c, we can denote that point d bisects segment ac.

we will call ac the base.

using the distance formula

ac = √((0 - 6)² + (-6 - 0)²)

ac = √72

knowing our base and our height, we can plug these into our triangle area formula

area = (b * h)/2

area = (√18 * √72) / 2

area = (√1296) / 2

area = 36 / 2

area = 18 units²