A slide has a diagonal of 10 feet and covers a distance of 8 feet across the ground. How many feet high is the slide at its highest point?

So, this creates a triangle once again. If we imagine a slide, the slide itself would be the hypotenuse of the triangle, then if there's a ladder leading up to the slide, that would be the vertical length we're looking for. The feet across the ground would be the distance from the bottom of the slide to the bottom of the ladder.

We can use the Pythagorean theorem to find the missing side length, as this would create a right triangle. | 8^2 + b^2 = 10^2 | 64 + b^2 = 100 | b^2 = 36 | b = 6 feet | The slide is 6 feet high at its highest point.

idk

step-by-step explanation:

i don't know