The slope intercept form of the equation of a line that passes through point (-3, 8) is y
= - 4x + 6. What is the point-slope form
of the equation for this line?
y-3= -? (X + 8)
y +3= ? (- 8)
y+8= _?_(x-3)
y-8= -
(x + 3)
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It is 6% because if you subtract 69-58=6 so 6% is the answer to your question.

So the first thing we do is to multiply the top equation by 3. the reason i want to do this is i notice there will be a 6y on both equations and can possibly add/subtract them. so we get 6y = -3x + 27. adding that and the second equation we get 6x = 27-15 which is 12. divide by 6 and we get 2. ∴ x = 2. substituting 2 into the first equation we get 2y = -2 + 9 which is 7. divide by 2 and we get 7/2. ∴ y = 7/2, x = 2.

Subtract 2 from all the first numbers and add 3 to all the second ones for new coordinates