A leasing firm claims that the mean number of miles driven annually, µ, in its leased cars is less than 12260 miles. A random sample of 15 cars leased from this firm had a mean of 11529 annual miles driven. It is known that the population standard deviation of the number of miles driven in cars from this firm is 2760 miles. Assume that the population is normally distributed. Is there support for the firm’s claim at the 0.05 level of significance? Carry your intermediate computations to at least three decimal places.

i need more information to answer

this is a very good question

step-by-step explanation:

i got a hair cut today from my mom not to flex just to flex kim jon un is one rad fellow i'd say you'd need to take the hairline in kinda like a box shape like someone rammed a lego brick into your head. from there you really need to take the top up keeping with that boxy aesthetic, finally coat the whole thing with gel if your country economics are failing or whatever you can just coat it with the starving children's food rations. about 5 orphans per strand is a good ratio. good luck with the fresh cut my dude

4444444444444 i think

$4034.40

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40