Plz help me asap i put 20 pts on line ill choose brainliest cus thats what yall want

A certain soup can has a label which, when peeled off the can has an area of 45 square inches. The height of the can is 6 inches. What is the radius of the soup can, rounded to the nearest tenth of an inch?

Radius = inches

7.5/π inches or 2.3885350318  inches.

Step-by-step explanation:

Given 45 sq inches as the lateral area of the cylinder, and the height being 6, we can use the simple equation a=h(π*2r). a/h, or 45/6 is 7.5. We can stop there and assume the answer is 7.5/π inches is the answer... Assuming pi is 3.14, 7.5 over 3.14, the answer (11 decimal places) would be 2.3885350318  inches.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3