Geometry question, brainliest goes to best answer. Please do all 3

MA = 30

MR = 30 sqrt(2)

SA = 2400

Step-by-step explanation:

Call the point at the bottom of the altitude Q

We can find QS by using the Pythagorean Theorem

a^2+b^2 = c^2  where the legs are PQ and QS and the hypotenuse is PS

20^2 + QS^2 =25^2

400 + QS^2 = 625

Subtracting 400 from each side

QS^2 =225

Taking the square root of each side

QS = 15

Doubling this length is the distance across the square

2QS = 2*15 = 30

This is the distance MA = 30

We can use the Pythagorean theorem again to find MR

a^2+b^2 = c^2  where the legs are MA and AR and the hypotenuse is MR

MA = 30  and AR =30 since this is a square

30^2 + 30 ^2 = MR^2

900+900 = MR^2

1800= MR^2

Taking the square root of each side

sqrt(1800)= sqrt(MR^2)

30 sqrt(2) = MR

surface area of a square pyramid is the area of the base + the area of the side  times fours (since we have 4 identical sides)

area of the base is MA*AR  = 30*30 = 900

The area of the side is 1/2 bh  since it is a triangle

 1/2 (AR) (PS) = 1/2 (30) 25) =375

Multiply this by 4 since we have 4 sides

375*4 =1500

Add this to the base

1500*900 =2400

MA = 30

MR = 30sqrt(2)

SA = 2400

Step-by-step explanation:

½MA:

sqrt(PS² - alt²)

sqrt(25² - 20²)

sqrt(225)

15

MA = 2 × 15 = 30

MR² = 30² + 30²

MR² = 1800

MR = sqrt(1800)

MR = 30sqrt(2)

Base + 4 triangles

30² + 4(½ × 30 × 25)

2400

i think it might be a but you might want a second opinion