Find the vertices and foci of the hyperbola with equation quantity x plus 5 squared divided by 81 minus the quantity of y minus 3 squared divided by 144 = 1. Vertices: (4, 3), (-14, 3); Foci: (-20, 3), (10, 3) Vertices: (3, 7), (3, -17); Foci: (3, -17), (3, 7) Vertices: (7, 3), (-17, 3); Foci: (-17, 3), (7, 3) Vertices: (3, 4), (3, -14); Foci: (3, -20), (3, 10)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.

it is 570

step-by-step explanation:

i dont understand

step-by-step explanation:

a ≈ 172.05

step-by-step explanation:

the pictures.