URGENT!
A ball is thrown into the air with an initial upward velocity of 48 feet/second. If height h in
feet after t seconds is given by the function h(t) = – 16t2 + 48t + 4.
a) What height will the ball be when 2 seconds has passed?

b) In how many seconds will the ball reach its maximum height?

c) What is the ball’s maximum height?

4.

step-by-step explanation:

it have the same area.brainliest

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)