Identify m∠BHJ.

The figure shows a circle with two tangents B H and J H. The secants intersect at point H in the exterior of the circle. The measure of arc B J is 105 degrees.

Answers:
m=52.5
m=127.5
m=70
m=75

m∠BHJ = 75°

Step-by-step explanation:

It is given that mBJ=105∘

Find mBMJ

mBMJ=360∘−105∘=255∘

If two tangents intersect in the exterior of a circle, then the measure of the angle formed is half the difference of the measures of its intercepted arcs. So,

m∠BHJ=12(mBMJ−mBJ)

Substitute the given values and simplify.

m∠BHJ=12(255∘−105∘)

=12(150∘)

=75∘

Therefore, m∠BHJ=75∘

8(-10x+3.5y-7)

8×-10x + 8×3.5y + 8×-7

-80x + 28y - 56

therefore

-80x+28y-56 is the correct answer

3/6   and 9/18

step-by-step explanation: