Mathematics, 24.04.2020 22:12 AutumnJoy12

Using grouping, factor 2 a2 – 13a + 21.

a. y = (2a + 7)(a + 3)
b. y = (2a + 7)(a − 3)
c. y = (2a – 7)(a + 3)
d. y = (2a – 7)(a − 3)

Answers: 1

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Using grouping, factor 2 a2 – 13a + 21.

a. y = (2a + 7)(a + 3)
b. y = (2a + 7)(a − 3...

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Using grouping, factor 2 a2 – 13a + 21.a. y = (2a + 7)(a + 3)b. y = (2a + 7)(a − 3)c. y = (2a – 7)(a + 3)d. y = (2a – 7)(a − 3)

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Another question on Mathematics

Using grouping, factor 2 a2 – 13a + 21.

a. y = (2a + 7)(a + 3)
b. y = (2a + 7)(a − 3)
c. y = (2a – 7)(a + 3)
d. y = (2a – 7)(a − 3)