Ahmed and Gavin are playing both chess and checkers. The probability of Ahmed winning the chess game is 45\%45%45, percent. The probability of Ahmed winning the checkers game is 0.360.360, point, 36. Which of these events is more likely? Choose 1 Choose 1 (Choice A) A Ahmed wins the chess game. (Choice B) B Ahmed wins the checkers game. (Choice C) C Neither. Both events are equally likely.

A) Adams wins the chess game

Step-by-step explanation:

Events with greater probability are more likely.

Let's put the probabilities in decimal form.

P(Ahmed wins the chess game) = 45%=0.45

P(Ahmed wins the checkers game)=0.36

0.45>0.36

It is more likely that Ahmed wins the chess game

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3

eight hundred an fifty one point four hundred and fifteen

800+50+1+.4+.01+.005