Practice solving problems involving two-step inequalities.
4 number lines going from negative 6 to positive 10. Graph A has an open circle at 2 with everything shaded to the right. Graph B has an open circle at negative 2 with everything shaded to the right. Graph C has an open circle at 0 with everything shaded to the left. Graph D has an open circle at negative 2 with everything shaded to the left.

Which number line shows the solution to
11x + 14 < –8?

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

8/k

step-by-step explanation:

answer:

step-by-step explanation: