Josiah has a mass of 75\text{ kg}75 kg75, start text, space, k, g, end text and wants to know how many helium-filled balloons it would take to fly. The density of helium is about 1\text{ kg/m}^31 kg/m 3 1, start text, space, k, g, slash, m, end text, cubed less than regular air, which means a cubic meter of helium can lift about 1\text{ kg}1 kg1, start text, space, k, g, end text. Fully inflated, a balloon has a diameter of 0.3\text{ m}0.3 m0, point, 3, start text, space, m, end text and can be modeled as a sphere. He neglects the mass of the balloon in his calculations. About how many balloons would it take to lift Josiah?

true

step-by-step explanation:

positive

step-by-step explanation:

the quadrant is facing upwards

answer: b

step-by-step explanation: im sorry bro bro but thats not a eqation the human mind can answer and plus im a devil

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages