1) Let X represent the number of tires with low air pressure on a randomly chosen car. The probability of distribution of X is as follows:
X 0 1 2 3 4
P(X) 0.1 0.2 0.4 0.2 0,1

a) Find the probability of 1 tire with low air pressure P (1) =

b) Find the probability of more than 2 tires having low air pressure P (more than 2) =

c) P (all 4 tires) =

d) Compute the expected number of tires with low air pressure.

e) Compute the standard deviation for the number of tires with low air pressure.

0.84 dang lotta people are looking for this lol or if you round up its 1 but the overall answer to that is 0.84

step-by-step explanation:

54 km / hours

step-by-step explanation:

we need to convert seconds to hours

60 seconds = 1 minutes

60 minutes = 1hour

15 m         60 second   60 minutes

  * *         = 54000 meters/ hour

second     1 minute             1 hour

now we need to convert meters to km

1000 m = 1 km

54000 m       1 km

*   = 54 km / hours

hour               1000m

27

step-by-step explanation: