The number 42 has the prime factorization 2 · 3 · 7. Thus 42 can be written in four ways as a product of two positive integer factors (without regard to the order of the factors): 1 · 42, 2 · 21, 3 · 14, and 6 · 7. Answer a–d below without regard to the order of the factors. (a) List the distinct ways the number 910 can be written as a product of two positive integer factors. (Enter your answer as a comma separated list of products.) (b) If n = p1p2p3p4, where the pi are distinct prime numbers, how many ways can n be written as a product of two positive integer factors? (c) If n = p1p2p3p4p5, where the pi are distinct prime numbers, how many ways can n be written as a product of two positive integer factors? (d) If n = p1p2 pk, where the pi are distinct prime numbers, how many ways can n be written as a product of two positive integer factors?

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!