A half-century ago, the mean height of women in a particular country in their 20s was 64.2 inches. Assume that the heights of today's women in their 20s are approximately normally distributed with a standard deviation of 1.85 inches. If the mean height today is the same as that of a half-century ago, what percentage of all samples of 20 of today's women in their 20s have mean heights of at least 65.33 inches?

i dont know their was no answer choice jiggaboo

(im black)

step-by-step explanation:

y=−9/2x+10

step-by-step explanation:

let's solve for y.

0−9x−2y=−20

step 1: add 9x to both sides.

−9x−2y+9x=−20+9x

−2y=9x−20

step 2: divide both sides by -2.

−2y

−2

=

9x−20

−2

y=

−9

2

x+10

d. millimeters per hour.

step-by-step explanation:

we are given that,

carlo used a rain gauge to measure the amount of water his lawn is receiving from the sprinklers.

since, according to the options, we see that,

water cannot be measured by 'miles per hour', 'meters per second' and 'grams per seconds'.

we get that, the water can be measured by 'millimeters per hour'.

hence, the appropriate rate for describing the amount of water is 'millimeters per hour'.

x+14

step-by-step explanation: