A simple random sample of 55 screws supplied by a certain manufacturer is obtained, and the length of each screw is measured. The sample mean is found to be 0.878 in. Assume that the standard deviation of all such lengths is 0.014 in, and use a 0.05 significance level to test the claim that the screws have a mean length equal to 7 divided by 8 in (or 0.875 in), as indicated on the package labels. Do the screw lengths appear to be consistent with the package label?

answer: 25.4 units

step-by-step explanation: radius = 12.7 units

diameter = twice the radius

diameter = 12.7 x 2

= 25.4

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3

it is c, trust i got your back lol

step-by-step explanation: